40k^2=360

Solution for 40k^2=360 equation:

40k^2=360

We move all terms to the left:

40k^2-(360)=0

a = 40; b = 0; c = -360;
Δ = b2-4ac
Δ = 02-4·40·(-360)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*40}=\frac{-240}{80}
=-3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*40}=\frac{240}{80}
=3
$